1 ELEC2133 Analogue Electronics QUESTION 1 [50 marks] The circuit shown in Fig. 1(a) is a sensor readout circuit developed by the MEMS/NEMS research group at EE&T, UNSW. Though simple in design, it is highly effective for amplifying the small electrical signal (voltage) generated by a PZT thin film in a micro-lens actuator during resonance. PZT, or lead zirconate titanate, is a piezoelectric material that converts mechanical strain into electrical charge (voltage), and vice versa—applied voltage into mechanical strain. This dual functionality makes PZT ideal for constructing actuators, which are devices that convert electrical energy into mechanical motion. Piezoelectric actuators enable extremely precise nanoscale movements and are widely used in advanced instrumentation, robotics, automotive systems, energy harvesting devices, and more. In addition to actuators, PZT is also used in sensors to detect minute movements, pressure, and forces. Applications include touch screens, pressure sensors, accelerometers, gyroscopes, and other precision sensing technologies. Fig. 1(b) shows the sensor readout circuit with the PZT actuator replaced by its electrical equivalent circuit that consists of a voltage source (VPZT) in series with a capacitor (CPZT). When the actuator is excited (driven) by Vin, it resonates and generates a small VPZT. (a) 2 (b) Fig. 1: Charge readout circuit (a) with piezoelectric actuator; (b) the piezoelectric actuator replaced by an equivalent circuit. PART 1 (Gain Calculation) [20 marks] (a) [P,C] Obtain the expression for the output voltage (Vo) of the amplifier when the actuator is driven (excited) by an AC source Vin operating at a frequency ω. [Hint: apply superposition principle and express the sources and the capacitor in complex frequency]. [5 marks] (b) [D] The purpose the readout circuit is to selectively amplify the VPZT and reject any output due to Vin (Vo due to Vin is to be zero). How can the purpose of the amplifier circuit be achieved based on your expression in (a)? [5 marks] (c) [P,C] Assuming R1 = R2, C1 = C2 = CPZT and R5 ≫ 1/2, obtain the expression for the gain of the amplifier (Vo/VPZT). [5 marks] (d) [HD] Could you suggest a modification to the readout circuit (or new altogether) that improves the gain of the amplifier and better achieve the purpose of the circuit. [5 marks] PART 2 (Frequency response) [15 marks] In reference to Fig. 1(a), the op-amps have large signal limitations and other characteristics as provided in Table 1. Assuming the bandwidth of the readout circuit is limited by the noninverting amplifier stage (the last stage) and R4 = 1k and R3 = 280k , Large signal limitations Output voltage saturation ±13V Output current limits ±20mA Slew rate 0.5V/µs Other characteristics Internal compensation capacitor 30pF Open loop voltage gain 100dB Open loop bandwidth 6Hz Table 1: The non-ideal op-amp characteristics (a) [P, C] Estimate the bandwidth of the readout circuit. [5 marks] (b) [P, C] With Vin = VAcos(ωt) and VA=1V and assuming VPZT = 0.005Vin, will there be a frequency at which the output (Vo) will be distorted? If so, what is that frequency? [5 marks] 3 (c) [D] With Vin = VAcos(2π*900t) and assuming R5 = 0.5M , R4 = 1k , R3 = 280k , R1=1k , R2=1k , C1 = C2 = CPZT = 10nf, what is the constrain on the VA if the output is to be undistorted? [5 marks] PART 3 (DC imperfection) [10 marks] (a) [HD] In the non-ideal case, the non-inverting op-amp (last stage) in Fig. 1 has the following DC imperfections. Assume all the other op-amps are ideal. Input bias current: IB = 40nA at room temperature Input offset current: Iio = ±2nA at room temperature Input offset voltage: Vio = ±2mV at room temperature Calculate the worst-case output offset voltage at room temperature assuming R5 = 500k , R4 = 1k , R3 = 280k , R1=1k , R2=1k , C1 = C2 = CPZT = 10nf. [Hint: Consider the DC imperfections in all the op-amps. In DC, capacitor can be regarded as open] ` [10 marks] PART 4 (Simulation) [5 marks] [P,C] Using LTspice or Pspice simulation, confirm your answer for part 1(c), part 2(a), part 3 (a). You may use LM301 op-amp and its model for the simulation. The op-amp is used in the first lab. [5 marks] 4 QUESTION 2 [50 marks] In Question 1, you analysed and designed the charge readout circuit for the PZT actuator shown in Fig. 1(a). A common issue with this circuit is that the final stage—the non-inverting amplifier—tends to amplify low-frequency noise originating from the power supply or environmental vibrations affecting the actuator. Additionally, it can amplify any DC offsets introduced by earlier stages in the circuit. Minimizing output noise while maintaining adequate signal amplification is crucial. Although there are various ways to improve the signal-to-noise ratio of the non-inverting amplifier, in this assignment it will be replaced with a three-stage transistor amplifier, as shown in Fig. 2(a). Your task is to analyse this new amplifier by calculating its gain, input and output impedance, and bandwidth. Fig. 2: A three-stage transistor amplifier The three-stage amplifier consists of one n-channel MOSFET transistor Q1 in depletion mode with W/L = 1 and two BJT transistors Q1 and Q2. The transistors have the model parameters as provided in the table below 5 PART I (Amplifiers configuration) [5 marks] (a) [P] Identify the amplifier configuration used in each stage of the amplifier.[1.5 marks] (b) [P,C] what are the functions of C1, C2, C3, C4, and C5 capacitors? [1.5 marks] (c) [P,C] Explain what are the purposes of each amplifier, and can a single-stage transistor amplifier (say stage 1 or 2 or 3) be used instead? [Hint: what are the requirements of voltage amplifiers in terms of input and output resistance? Remember the non-inverting amplifier (the last stage) in Fig. 2 is a voltage amplifier] [2 marks] PART II (Q-point and transistor model parameter calculations) [13 marks] (a) [P] Draw the DC equivalent circuit of the transistor amplifier in Fig, 2. Note that capacitors act as open circuit in DC conditions. [2 marks] (b) [P,C]Show that the Q-Point values are: M1(ID=5mA, VDS=10.9V), Q1 (IC=1.51mA, VCE = 5.49V), and Q2 (1.99mA, 8.44V). [6 marks] (c) [P,C] Calculate the transistor model parameters for each transistor, namely gm1, gm2, gm3, ro1, r02, ro3, rπ2 and rπ3. [2 marks] (d) [D] *Comment on the possible range of resistance values that may replace the RC2 = 4.7k , RD2 = 0.62k of the BJT Q1 transistor in the amplifier. [Hint: BJT must operate in a forward-active region and MOSFET must operate in a saturation region] [3 marks] PART III (Calculating mid-band gain, input, and output resistance) [13 marks] (a) [P,C] Draw a small-signal equivalent circuit of the amplifier in the form suitable for mid-frequency. [3 marks] (b) [DN] Calculate the mid-band voltage gain of the amplifier, input resistance and output resistance. [6 marks] (c) [HD] Calculate the mid-band current and power gain [4 marks] PART IV (Calculating bandwidth) [14 marls] (a) [P,C] Draw small-signal equivalent circuit of the amplifier in the form suitable for low frequency. [2.5 marks] (b) [D] Calculate the lower 3dB frequency, fL, of the amplifier using the appropriate time constant method. [4.5 marks] 6 (c) [P,C] Draw small-signal equivalent circuit of the amplifier in the form suitable for high-frequency analysis. [2.5 marks] (d) [DN, HD] Calculate the higher 3dB frequency, fH, of the amplifier using the appropriate time constant method. [4.5 marks] PART V (LTSpice or PSpice Simulation) [5 marks] (a) [DN] Simulate Fig. 2 and compare the results with your calculation of midband gain and bandwidth. The Spice transistor models will be uploaded on Moodle. [5 marks]
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